Question

The given figure shows a ray of light as it travels from medium A to medium B. The refractive index of medium B relative to medium A is:​

Answer 1

The Snell's law simply relates angles i and r to the refraction indices of the two media A and B. Therefore, refractive index of medium B relative to medium A is:

$n = \frac{ \sin(i) }{ \sin(r) } = \frac{ \sin(60) }{ \sin(45) } = \frac{ \sqrt{3} }{ \sqrt{2} }$