Question

the given figure shows a rectangle .Find the area of the shaded region ​

Answer 1

Answer:

Step-by-step explanation:

ANSWER:-

Given that:-

• The figure is an rectangle,
• The sides are mentioned

Concept:-

• To remember that rectangle has 90 degrees as angle.
• Area of right angles triangle
• Area of rectangle

Let's Do!

$\sf{Area \ of \ Right \ Angle \ Triangle = \dfrac{1}{2} \times Base \times Height}$

Calculating area 1 of triangle:-

$\dfrac{1}{2} \times 10 \times 14$

$\implies 70 \ \rm{cm^2}$

Now, area 2, as mentioned:-

$\dfrac{1}{2} \times 3 \times 18$

$\implies 27 \ \rm{cm^2}$

Now, area 3, :-

$\dfrac{1}{2} \times 7 \times (18-14)$

$\dfrac{1}{2} \times 7 \times 4$

$\implies 17 \ \rm{cm^2}$

Adding 1+2+3, we get

70+27+17 = 114 cm^2

Now, area of the whole rectangle:-

$\sf{Area \ of \ Rectangle = Length \times Breadth}$

$= 18 \times 10$

$= 180 \ \rm{cm^2}$

So now area of shaded region:-

$180 -114 = \boxed{\sf{66 \ cm^2}}$

So, that's the answer.

Answer 2

Answer:

$\huge \sf \: required \: answer$

As we know that

$\sf \: area \: of \: right \: angle \: triangle \: = \frac{1}{2} \times b \times h$

Area of 1st triangle

$\frac{1}{2} \times 10 \times 14$

$5 \times 14 = {70 \: cm}^{2}$

Area of 2nd triangle

$\frac{1}{2} \times 3 \times 18$

$3 \times 9 = {27 \: cm}^{2}$

Area of third triangle

$\frac{1}{2} \times 7 \times (18 - 14)$

$\frac{1}{2} \times 7 \times 4$

$7 \times 2 = {14 \: cm}^{2}$

Adding of all triangle

$70 + 27 + 17 = {114 \: cm}^{2}$

Finding area of rectangle

$\sf \: area \: = length \: \times breadth$

$area \: = 18 \times 10$

$area \: = {180 \: cm}^{2}$

So, shaded region

$\sf \: 180 - 114= 66$

$\huge {\fbox {\red { {66 \: cm}}}}$