Question

The given figure shows a square ABCD of side 14 cm.Two semicircles are drawn each side as diameter.What is the area of shaded region? ( π = 22/7)

Answer 1

Answer:

3.31

Step-by-step explanation:

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Answer 2

The area of the overlapped zone is 28 cm².

Step-by-step explanation:

Consider the quarter part of the large square, where the quarter circles intersect.

See the attached diagram.

The two-quarter circles each will have the area of  $\frac{1}{4}\pi r^{2} = \frac{1}{4}\times \frac{22}{7}\times 7^{2} = 38.5$ cm².

And the area of the quarter square is (7 × 7) = 49 cm²

Therefore, the area of the overlapped zone = 2 × 38.5 - 49 = 28 cm². (Answer)