Question

the given figure shows a triangle ABC in which ad is perpendicular to side BC and BD = CD prove that triangle ABCD is congruent to triangle ACD and ab = AC and Angle B equal angle C

Answer 1

Answer:

Step-by-step explanation:

Given AD as a common bisector and BC as a common base

In tri ADB

By pt

AB^2=BD^2+AD^2

AND

IN TRI ADC

AC^2=AD^2+DC^2

NOW

AD IS A COMMON BISECTOR

SO

AB^2 -DC^2=AD^2

PUT THESE VALUE IN NEXT EQ

NOW