the given figure shows three resisters. find the combined resistance R1=6 ohm, R2=2 ohm, R3=6 ohm
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firstly tell me this resistance combine in series or parallel in case it is series so Rs= R1+R2+R3
6+2+6
=14 ohm
but in parallel so
1/Rp=1/R1+1/R2+R3
=1/6 +1/2+1/6
=1+3+1÷6(because we take L.C.M )
=5/6 ohm answer
6+2+6
=14 ohm
but in parallel so
1/Rp=1/R1+1/R2+R3
=1/6 +1/2+1/6
=1+3+1÷6(because we take L.C.M )
=5/6 ohm answer
Zsparsh:
parrallel
sorry series
so i gave answer in both case ok
Ok
Bro r1 and r2 are parallel and r3 is series
i have no diagram i do with my concept i can send daigram
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