Question

The given figure the shape of the top of table is that sector of centre O and angle AOB= 90°.If AO =OB=42 cm then perimeter of the top of the table is __________

Answer 1

Length of arc. Of a particular angle(θ,here)
Is given by (θ/360°).2πr
Where r is 42cm in the given fig.

And θ is 360-AOB=270°

=> perimeter or length of given arcAB
=(270/360).2.(.22/7).42
=198

Answer 2

Answer:

Step-by-step explanation:

Perimeter of the top of the table=(circumference-(perimeter of sector))

=(2×22/7×42)-(2×22/7×42×90/360)+(2×42)cm

=282cm.