the given figure, the value of PM
(A) 3 (B) 4
(C) 5 (D) 2
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in triangle OLP and triangle OMP,
angle OLP=angle OMP=90°
OP=PO(common side)
angle LOP=angle POM(given)
by RHS congruence
therefore, triangle OLP =~ triangle OMP
OL=OM=3cm(By CPCT)
in triangle OMP,
OM²+PM²=OP²
3²+PM²=5²
PM²=5²-3²
PM²=25-9
PM²=16
PM=√16
PM=4cm
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