the given frequency distribution the students the number of passengers who board at particular day time 5-8, 8-11 ,11-14 ,14-17 ,17- 20, 20- 23 number of passengers 40 90 44 58 53 10 find the mode and median of the given data
Answers
Step-by-step explanation:
The given frequency distribution represent the number of passenger who boarded a local bus during a particular day time and no. Of passenger 5-8 =40,8-11 =90,11-14 =44,14-17 =58,17-20 =53,20-23 =10. Find the mode and median of the above data
Median=12.19
Mode=9.56
Step-by-step explanation:
Sum of all frequencies=
N is odd therefore,
Median class= observation=
148 lies in interval 11-14
Median=
Where h=Size of class
N=Sum of frequencies
l=Lower limit of median class
f=Frequency of median class
c.f=Cumulative frequency of the class preceding median class
We have l=11,h=3,f=44,c.f=130
Substitute the values in the formula
Median=
Median=
Mode=
Where l=Lower limit of modal class
Frequency of modal class
=Frequency of class preceding modal class
=Frequency of class succeeding the modal class
h=Size of class
Modal class: The class whose frequency value is highest
Modal class=8-11
l=8,h=3,
Substitute the values in the formula
Mode=
Mode=9.56
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