Question

The given line passes through the points (0, −3) and (2, 3). What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (−1, −1)? y + 1 = (x + 1)

Answer 1

I think the answer is y+1=3(x+1)

not y+1=(x+1)

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Answer 2

the given line passes through the the points (0,-3)  and (2,3)

so,x1=0, x2=2, y1= -3 ,y2=3:

the slope(m1) of the given line=m1=y2 - y1/x2 -x1  =(3-(-3))/(2-0)=6/2=3

hence,m1=3

the line that is parallel to the given line has slope(m2)

as we know,the slopes of two parallel lines ⇒m1=m2

∵m1=3    so m2 also equal to 3

∴m2=3

it passes through the points (-1,-1)

(if we have one slope and one point then we can apply this formula for finding the eq)

(y-y1)=m2(x-x1)

y1= -1 and x1= -1(putting these values )

(y-(-1))=3(x-(-1))

(y+1)=3(x+1)          it's the req eq