Question

the given number is increased by 20% and the resulting number is again increased by 25% .what is the net percentage increase in the number​

Answer 1

let the no. be x

then,

$x + \frac{x}{100} \times 20$

$x + \frac{x}{5}$

$\frac{6x}{5}$

now the no. again increased by 25%,

$\frac{6x}{5} + \frac{6x}{5} \times \frac{1}{100} \times 25$

$\frac{6x}{5} + \frac{6x}{5 \times 4}$

$\frac{24x + 6x}{20}$

$\frac{3x}{2}$

the total percentage increased is,

$\frac{3x}{2} \times \frac{1}{x} \times 100$

$\frac{3 \times 100}{2}$

$150\%$

so,

total increased is 150%