the given pair of linear equation have infinitely many solutions nine x + K Y + 12 is equal to zero of 18 x + 6 Y + 24 is equal to zero then value of k is
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Step-by-step explanation:
now here given equations are x+ky+12=0
ie x+ky=-12
also 18x+6y+24=0 ie 18x+6y=-24
so now comparing x+ky=-12 with a1x+b1y=c1
we get a1=1 b1=k and c1=-12
also comparing 18x+6y=-24 by a2x+b2y=c2
we get a2=18 b2=6 c2=-24
now as both equations have infinitely many solutions
a1/a2=b1/b2=c1/c2
so 1/18=k/6=-12/-24
so consider 1/18=k6
ie k=3
hence value of k is 3
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