Question

the given plane figure is to be coloured what will be the expenditure at the rate of rs.15 per m² ​

Answer 1

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Here is your answer

There are two trapezium in the figure

For I

Area =1/2(Sum of parallel sides)(Distance between them)

\begin{gathered} = \frac{1}{2} \times (7 + 4) \times 4 \\ = 11 \times 2 \\ = 22m {}^{2} \end{gathered}

=

2

1

×(7+4)×4

=11×2

=22m

2

For I

Area is

\begin{gathered} = \frac{1}{2} \times (4 + 8) \times 5 \\ = \frac{1}{2} \times 12 \times 5 \\ = 6 \times 5 \\ = 30 \: m {}^{2} \end{gathered}

=

2

1

×(4+8)×5

=

2

1

×12×5

=6×5

=30m

2

Total Area = 22+ 30

= 52 sq m

Rate of Colouring = Rs 15 sq m

Therefore Expenditure in colouring the figure is

\begin{gathered} = 52 \times 15 \\ = 780 \: rupees\end{gathered}

=52×15

=780rupees