The given question is
The sum of n terms of two arithmetic progressions are in the ratio (3n+8) : (7n+15).find the ratio of their 12th terms.pls guys help i can't understand y they took n as 23?????
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1
by putting n=23
we can solve this problem
we can solve this problem
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pavi34:
why they are taking 23 here
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Heya Friend ☺
Here we need to understand the question first
The question is telling that we need to find the ratios of the 12 term of an Aps
for that we need certain assumptions that must had given in that very solution by using that and making some equations and breaking down in sum to n terms Formula here we got our first equation
After that According to question here we had put the first equation and made our second equation for finding sum to n terms through sn= 12 now by comparing both sides we got the number of terms that exist in the Aps is 23 after putting the value in any of the equation we will get the ratios
I hope it helps you ☺
Here we need to understand the question first
The question is telling that we need to find the ratios of the 12 term of an Aps
for that we need certain assumptions that must had given in that very solution by using that and making some equations and breaking down in sum to n terms Formula here we got our first equation
After that According to question here we had put the first equation and made our second equation for finding sum to n terms through sn= 12 now by comparing both sides we got the number of terms that exist in the Aps is 23 after putting the value in any of the equation we will get the ratios
I hope it helps you ☺
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