Question

The given series has the final term missing.


6,3, 18, 12, 54, 48, 162,?
​

Answer 1

here ,we make two series from it -

6,18,54,162 and

3,12,48,?

In first series pattern is ×3.

and in second series pattern is ×4.

So,?=48×4=192

So,?=192

Answer 2

192

6,3, 18, 12, 54, 48, 162, 192

Step-by-step explanation:

Given:

6,3, 18, 12, 54, 48, 162,?

To find:

The missing number      

Solution:

• This is a numerical sequence in which they are arranged in a manner that forms a series.
• We need to find the pattern for finding the missing number.
• This series we have to split up into two, 6⇒18⇒54⇒162 and 3⇒12⇒48⇒?

6⇒18⇒54⇒162

This was the series thus arranged with (x₁, x₁×3⇒x₂, x₂×3⇒x₃,x₃×3 ⇒x₄)

The pattern is thus arranged with every term(x₁,x₂,x₃,x₄) is multiplied by 3.

3⇒12⇒48⇒?

This was the series thus arranged with (x₁×4⇒x₂,x₂×4⇒x₃,x₃×4⇒ x₄).

The pattern is thus arranged with every term(x₁,x₂,x₃,x₄) is multiplied by 4

Thus the final missing term was x₄⇒x₃×4

                                                       ⇒48×4

                                                       ⇒192

Hence,

The final term missing is 192.

6,3, 18, 12, 54, 48, 162, 192.