Question

The given system is displaced by distance 'A' and released. Both the blocks (each of mass m) move
together without relative slipping in the whole process. The magnitude of frictional force between them
at time t'is :
​

Answer 1

Answer:

The magnitude of frictional force between them  at time t is

$F_f = \frac{kA}{2} cos(\sqrt{\frac{k}{2m}})t$

Explanation:

As we know that both books are moving together and they start from their maximum displacement position

So we will have

$\omega = \sqrt{\frac{k}{2m}}$

now we know that

$x = A cos(\sqrt{\frac{k}{2m}})t$

now the acceleration of the two books at any instant of time is given as

$a = - \omega^2 x$

$a = -\frac{kA}{2m} cos(\sqrt{\frac{k}{2m}})t$

now the friction force between them is given as

$F_f = ma$

$F_f = \frac{kA}{2} cos(\sqrt{\frac{k}{2m}})t$

#Learn

Topic : SHM

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