The given table shows the freezing point in °F of different gases at sea level. Convert each of these into °C to the nearest integral value using the relation and complete the table C=5/9(F-32)
Answers
Answer:
Given relation is C=
9
5
(F−32)
For hydrogen;
F
∴C
=−435
0
F
=
9
5
(−435−32)
=
9
5
(−467)
=−
9
2335
=−259.44
∘
C
For Krypton;
F
C
=−251
0
F
=
9
5
(−251−32)
=
9
5
(−283)
=
9
−1415
=−157.22
∘
C
For Oxygen;
F=−369
0
F
C=
9
5
(−369−32)
=
9
5
(−401)
=
9
−2005
=−222.77
∘
C
For Helium;
F=−458
0
F
C
=
9
5
(−458−32)
=
9
5
(−490)
=
9
−2450
=−272.22
∘
C
For Argon;
F=−309
0
F
C
=
9
5
(−309−32)
=
9
5
(−341)
=
9
−1705
=−189.44
∘
C
Step-by-step explanation:
We have, C=59(F−32)
For Hydrogen, put F= (-435)
⇒C=59(−435−32)=59×(−467)=−259.44⇒C=−259.44⇒C = −259
For Krypton, put F= (-251)
⇒C=59(−251−32)=59×(−283)=−157.22⇒C=−157.22⇒C=−157
For Oxygen, put F = (-369)
C=59(−369−32)=59×(−401)⇒C=222.7⇒C=223
For Helium, put F = (-458)
C=59(−458−32)=59×(−490)=−272.22⇒C=−272.22⇒C=−272
For Argon, put F = (-309)
C=59(−309−32)=59(−341)=−189.44⇒C=−189.44⇒C=−189
