Question

the given v - t graph shows the motion of an object .​

Answer 1

Answer:

1) O to A...

accleration = 6/4 = 1.5 m/s² .. accelerated motion

2) A to B.. velocity constant ... accleration zero

3) B to C ... deaccelerated motion... accleration = -6/6 = -1

distance covered = area under vt graph

1/2(6+16)×6 = 66 m

hope this will help you

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