Question

The given velocity- time graph showing the motion of a wheel of 5kg moving along a straight line on a road. How much force does the road exert on the wheel to bring it to rest?

A, 2N
B. 10N
C. -10N
D. 8N ​

Answer 1

Answer:

answer is -10N

Step-by-step explanation:

the formula is :-

f = m(v-u)/t

f = 5(0-20)/10

5 and 10 cancel out with eachother

so; f = 0-20/2

-20/2  is divided by eachother

and the answer is -10

and sorry if you not understand my answer

Answer 2

Given:

Mass of wheel = 5 kg

Initial velocity, u = 20 m/s

Final velocity, v = 0 m/s

Time duration, t = 10 seconds

To Find: Force exerted by the ground on wheel to put it to rest

Calculation:

• Force exerted on the wheel:

F = m * a

• a is the acceleration of the wheel which is given as:

$a=\frac{v-u}{t} = \frac{0-20}{10} =-2 m/s^{2}$

• Acceleration is in negative which means the body is decelerating.

• F = 5 * (-2) = -10 N

Answer:

Force exerted by the ground is the frictional force of 10 Newton in magnitude in the opposite direction of motion i.e. C. -10 Newton.

Your question is missing the graph, perhaps you are referring to the graph below: