The glider and pilot have a total mass of 492 kg. During the acceleration the glider is subject to an average resistive force of 160 n. Determine the average tension in the cable as the glider accelerates.
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Therefore the average tension in the cable is 1365.4 N.
Explanation:
Here a = m/s²=2.45 m/s²
F- resistance= m×a
F-160= 492×2.45
⇒F= 1205.4+160
⇒F= 1365.4 N
Therefore the average tension in the cable is 1365.4 N.
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