Question

the gradient of the curve y=4x^2-2x at X=
1​

Answer 1

Answer:

6 is the answer

Explanation:

gradient = (dy/dx) = 8x - 2

at x=1

dy/dx = 8 - 2 = 6

Answer 2

Answer:
Hence the gradient of the curve at x=1 is 2

Explanation:

• The equation of the curve given to us is
  $y=4x^2-2x$
• To find the gradient you have to find the slope of tangent at that point as that will be the gradient of curve at that point
• So we can find that we have to differentiate the curve at the given point
  $\frac{dy}{dx} = \frac{d(x^2-2x)}{dx} \\\frac{dy}{dx} = 2x-2$
• So by putting the value of x = 1 we get
  $\frac{dy}{dx} = 4-2 = 2$
• Hence the gradient of the curve at x=1 is 2
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