Math, asked by pachaurisahil321, 1 year ago

the gradient of the curve y= x^3-x^2 at (0,0) is​

Answers

Answered by rishabhpandey0217
1

Answer:

dy/dx =0

Step-by-step explanation:

dy/dx =3x^2-2x

at x=0 and y=0,

dy/dx= 0

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