Question

the gradient of the line joining points ( 7 , k ) and ( k , 3 ) is 4 upon 5 . calculate k .
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Answer 1

Answer:

Since slope here is 4/5,

and using coordinates the slopes are given by,

$\frac{y - y1}{x - x1}$

Using this relation we have,

$\frac{3 - k}{k - 7} = \frac{4}{5} \\ \\ 15 - 5k = 4k - 28 \\ 9k = 33 \\ k = \frac{11}{3}$

Answer 2

slope = y2-y1/x2 - x1

4/5 = 3-k/k-7

k = 11/3

hope it helps

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