THE GRADIENT OF xi+yj+zk is
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Answer:
grad(xi+yj+zk)=1+1+1=3
Explanation:
since gradient of any position vector is 3
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Given: A vector xi+yj+zk
To find: Gradient of the given vector
Solution: The gradient of any vector is nothing but a multi variable function and can be calculated by finding the derivative of each part of the vector
So partial derivative of the vector will be
∂f/∂x= 1
∂f/∂y= 1
∂f/∂z= 1
And the gradient is also a form of a vector that consists of these derivatives.
So, the gradient will be < 1,1,1 >
Therefore, the gradient of the given vector xi+yj+zk is < 1,1,1 >.
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