Question

the Gram of Noah present in 5ml in a 1% Noah are​

Answer 1

Answer:

As we know Molarity = no of moles of solute/Volume of solution in litres

i.e M = m/V(L)

M= Molarity of substance

m = number of moles of substance (i.e solute)

V(L) = volume of solution in Litres

So talking about our question molarity should be 0.5 M,volume should be 0.1 L , and we should know that Molar Mass of NaOH is 40 because Atomic mass of Sodium i.e (Na known as Natrium) is 23,Atomic mass of Oxygen (O) is 16 and Atomic mass of Hydrogen is 1.

Adding them all up gives Molecular mass of NaOH as 40

So if we solve above equation we get no of moles of NaOH present in 0.1 litres of solution

Let’s do that math

Rearranging equation we get m=M×V(L) i.e m= 0.5×0.1 =0.05. So 0.05 moles of NaOH are present in 100 ml of 0.5 Molar solution

Now we also know that to find no of moles of a substance we have a formula and it is m=W/Mw where

m = no of moles of a substance

W = Mass of substance

Mw = Molecular weight of the substance

So substituting all values and rearranging equation we get mass of NaOH as

W=m×Mw = 0.05×40=2 grams

Hence we found the required mass of NaOH as 2 grams.