The graph below shows a company's profit f(x), in dollars, depending on the price of goods x, in dollars, being sold by the company:
Unit 9 CR
Part A: What do the x-intercepts and maximum value of the graph represent?
Part B: What are the intervals where the function is increasing and decreasing, and what do they represent about the sale and profit?
Answers
Credits : sqdancefan (Brainly.com)
I changed some of it myself :)
Answer:
A) intercept: 0 profit : Maximum(max) : max profit. increasing x <4 ; decreasing x > 4
B) average slope: ≈50, about $50 increasing profit for each $1 increasing in price.
Step-by-step explanation:
A) The vertical axis of the graph represents profit, so the x-intercepts represent prices in the produce 0 profit. The maximum value of the graph is the maximum profit that can be obtained for anyprice
The higher or largest number of the chart is the maximum reach
B) We read the value of f(1) from the graph to be about 120, so the average rate of change is about ...
(f(4) -f(1))/(4 -1) = (270 -120)/(3) = 50
The average rate of the change from x = 1 to x = 4 is about 50.* This means profit will increase on average $50 for each $1 increase in price in what interval.
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* if we take the peak profit to be $270 we can write f(x) as ...
f(x) 16.875x(x-8)
Then f(1) = 118.15 ad average rate if changed is 50.625. For the purpose here, we judge the extra precision to be pointless
Answer:
A) intercept: 0 profit : Maximum : max profit. increasing x <4 ; decreasing x > 4
B) average slope: =50, about $50 increasing profit for each $1 increasing in price.
Step-by-step explanation:
hope this helped you have a great day!!! :DD