Question

the graph displaythe load against plot from metal wire of diameter 1.5 mm and origonal length 1m.when the load reaches tje value of point A the wirebroke .Fromthe graph deduce value of force cpnstant and the young modulus dor the metal of the wire​

Answer 1

Answer:

Explanation:

The applied load =F=mg=2×9.8=19.6N

diameter =1mm=1×10  

−3

m

=> radius=0.5×10  

−7

m

Area , A=3.14r  

2

=3.14×0.25×10  

−6

 

=0.785×10  

−6

 

We know that,

stress=Force/area

=19.6/0.785×10  

−6

 

24.96×10  

−6

 

change in length,ΔL=1mm=10  

−3

m

Length,L=3m

hencestrain=ΔL/L

=10  

−3

/3

we know that young's modulus is given by the ratio of stress and strain,

Hence,

E=24.96×10  

−6

/10  

−3

/3

=74.8×10  

9

 

=7.48×10  

10

Nm  

−2