The Graph given is the distance time graph of an object....a)find the speed of the object during the..!!
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During first four seconds, graph is a straight line making some angle with X axis . This means that body is moving with uniform speed.
From a distance time graph, to find speed, you need to find slope.
Slope = Change in y coordinate divided by change in x coordinate
During first 4 seconds,
Slope = (75-0)/(4-0) = 75/4 = 18.75
So, speed is 18.75 m/s for first 4
seconds.
From a distance time graph, to find speed, you need to find slope.
Slope = Change in y coordinate divided by change in x coordinate
During first 4 seconds,
Slope = (75-0)/(4-0) = 75/4 = 18.75
So, speed is 18.75 m/s for first 4
seconds.
QGP:
In the given figure, graph is a straight line parallel to x axis from t=4 s to t=14 s. So the body remains stationary for ∆t = 14-4 = 10 s
So, answer for part (b) is 10 seconds
c) The graph doesn't represent a realistic situation. Here's why:
The body is stationary till 14 seconds. The graph means that at t=14 seconds , time moves in backward direction till t=10 s and the distance decreases to zero
Both conditions are not possible
First, distance travelled can never decrease. (Displacement can decrease and become zero. But distance cannot)
Next, time cannot move in backward direction.
So, the graph doesn't represent a realistic situation.
I hope I have answered your question. If you have any doubts, feel free to ask
Tysm..!!
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Answer:
I don't know sorry
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