Question

the graph of a linear equation passes through the points (-1,4) and (2,1).find the values of p and q if the graph also passes through (p,3) and (1,q).
answer with solution

Answer 1

Answer:

p = 0

q = 2

Step-by-step explanation:

Equation for the line passing the points (-1,4) and (2,1):

$\frac{y - 4}{x - (-1)} = \frac{4 - 1 }{- 1 - 2} = - 1$

=> $y - 4 = - x - 1$

=> $x + y - 3 = 0$  . . . . . . . . . . . equation (i)

Given that (p, 3) passes through the straight line represented by equation (i)

∴ p + 3 - 3 = 0 => p = 0.

Also. (1, q) passes through the straight line represented by equation (i)

∴ 1 + q - 3 = 0 => q = 2.