Question

the graph of a linear equation x minus 5 Y + 3 equal to zero cut the x-axis at a point​

Answer 1

Answer:

it cuts the x axis at (-3,0)

Step-by-step explanation:

if it cuts the x axis , the y coordinate should be 0

so the point will be (x,0)

substitute y=0 in the equation x-5y+3=0

x= -3

hence the point is (-3,0)

Answer 2

SOLUTION

TO DETERMINE

The graph of a linear equation x - 5y + 3 = 0 cut the x-axis at a point

EVALUATION

Here the given equation of the line is

x - 5y + 3 = 0

Now the line cut the x-axis

Thus we have y = 0

From above Putting y = 0 we get

x - 0 + 3 = 0

⇒ x = - 3

Hence the required point is ( - 3,0)

FINAL ANSWER

The graph of a linear equation x - 5y + 3 = 0 cut the x-axis at a point ( - 3,0)

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