The graph of a linear equation y=9/5x+32y cuts the y-axis at the point
[1 mark]
(0 , -32)
(32 , 0)
(0 , 32)
(-32 , 0
Answers
Answered by
11
Option C is the correct answer of the question
Explanation
y=9/5+32
Put x=0
y=9/5x+32
y=9/5(0)+32
y=0+32
y=32
The coordinate is (0,32)
So the y cuts in 32 in y axis.
Answered by
4
Step-by-step explanation:
ur answer is option c...........
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