Question

the graph of equation 3x+5y=30 and dash represents parallel lines
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Answer 1

Answer:

The line has to be parallel to 3x−5y=30 and passing though the intersection of y=6x−5 and y=−2x+11 .

Solving for point of intersection

6x−5=−2x+11

8x=16

x=2

Substituting in either 2nd or 3rd equation which is y=6x-5 and y=-2x+11

y=6×2−5

y=7

Thus the point of intersection is 2,7

Slope of 1st line

3x−5y=30

y=3x/5−6

Slope m which is the coefficient of x in the equation is 3/5. While a point in this line is (2,7).

Substituting for m,x1 and y1 in the equation

y−y1=m(x−x1)

y−7=3/5(x−2)

y=3x/5−6/5+7

5y=3x−6+35

5y=3x+29

So final equation

5y=3x+29

Step-by-step explanation:

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Answer 2

ANSWER :

9X= -15Y

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