Math, asked by RAVITETARWAL0003, 9 months ago

The graph of g(x)=ax^2 is narrower than the graph of f(x)=x^2 when a>0. This is .....true


Sometimes


Always


Never

Answers

Answered by abhiarawal7792
34

Answer:

Step-by-step explanation:

as given in question that a > 0 so

if we put a=1

we get g(x) = f(x)

now put a =2

we get

g(x) = 2 f(x)

here we can see that g(x) would always be greater than or equals to f(x)

so we can say that the graph of g(x) will never be narrower than graph of g(x)

thank you

Answered by sujaypurakait096
5

Answer:

The given statement is SOMETIMES TRUE

Step-by-step explanation:

The graph of f(x)=ax^2 is narrower than the graph of g(x)=x^2 if a>1,

wider if a<1

and

equally wide if a=1 (because when a=1 then f(x)=x^2=g(x))

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