The graph of g(x)=ax^2 is narrower than the graph of f(x)=x^2 when a>0. This is .....true
Sometimes
Always
Never
Answers
Answered by
34
Answer:
Step-by-step explanation:
as given in question that a > 0 so
if we put a=1
we get g(x) = f(x)
now put a =2
we get
g(x) = 2 f(x)
here we can see that g(x) would always be greater than or equals to f(x)
so we can say that the graph of g(x) will never be narrower than graph of g(x)
thank you
Answered by
5
Answer:
The given statement is SOMETIMES TRUE
Step-by-step explanation:
The graph of f(x)=ax^2 is narrower than the graph of g(x)=x^2 if a>1,
wider if a<1
and
equally wide if a=1 (because when a=1 then f(x)=x^2=g(x))
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