The graph of linear equation 2x+3y=6cuts the y-axis at which point
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After plotting the graph of the equation, it can be interpreted that the graph cuts y-axis at the point (0,2).
ALITER
Every point on y-axis is of form (0,y). Let the point, which lies on y-axis, be (0,y).
Since the point lies on the graph of the equation, and every point on the graph of a linear equation is a solution of the equation, (0,y) is a solution of the equation at x=0 and y=y.
Thus, substituting the values of x and y in the equation, we have:
2(0)+3(y)=6
=>3y=6
=>y=6/3=2
Thus, the required point = (0,2)
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