the graph of linear equation 2x + y = -2 cuts the y axis at *
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Step-by-step explanation:
Since, the graph of linear equation 2x + 3y = 6 cuts the Y-axis.
So, we put x = 0 in the given equation 2x+ 3y = 6, we get
2 x 0+ 3y = 6 ⇒ 3y = 6
y = 2.
Hence, at the point (0, 2), the given linear equation cuts the Y-axis
Answered by
0
Answer:
line cuts at -2 in Y- axis and -1 in X- axis
so, in Y- axis at -2.
Step-by-step explanation:
to find X-interceptor take Y=0 like (X,0)
to find Y-interceptor take X=0 like (0,Y)
So, in line 2x+y = -2
we need Y-interceptor
∴ X=0
apply in x=0 in 2x+y=-2
⇒ 2(0)+y=-2
⇒ y = -2
To find X- interceptor same way apply
∴Y=0
⇒ 2x+0 = -2
⇒ 2x = -2
⇒ X = -1
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