Question

The graph of linear equation 3x + 2y = 16 cuts y-axis at

Answer 1

Answer:

The graph of the linear equation 3x + 2y = 16 cuts the Y-axis at the point  (0,8).

Step-by-step explanation:

Since, the graph of linear equation 3x + 2y = 16 cuts the Y-axis.

So, we put x = 0 in the given equation 3x + 2y = 16, we get

3 x 0+ 2y =1 6

=> 2y =16

y=8.

Hence, at the point (0, 8), the given linear equation cuts the Y-axis.

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