The graph of linear equation x+2y = 2, cuts the -axis at.find that
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Step-by-step explanation:
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x+2y=0 .......(1)
x−2y=0 .......(2)
Eqn(1)+Eqn(2)
x+2y+x−2y=0
⇒2x=0 or x=0
⇒x+2y=0⇒0+2y=0 or y=0
∴x=0,y=0
Answered by
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Answer:
ANSWER
x+2y=0 .......(1)
x−2y=0 .......(2)
Eqn(1)+Eqn(2)
x+2y+x−2y=0
⇒2x=0 or x=0
⇒x+2y=0⇒0+2y=0 or y=0
∴x=0,y=0
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