Question

The graph of linear equation X +3y = 2,cuts the y -axis at

Answer 1

Answer:

0,2/3

Step-by-step explanation:

In y axis x=0-- ->3y=2

y=2/3

Answer 2

$Given \: Linear \: equation \: in \: variables \: x$

$and \: y \: is : x + 3y = 2$

$put \: x = 0 \: in \: the \: equation, \:we \:get$

$\implies 0 + 3y = 2$

$\implies 3y = 2$

$\implies y = \frac{2}{3}$

$\therefore x+3y = 2 \:cuts \: the \: y -axis \:at$

$the \: point \: \Big( 0, \frac{2}{3}\Big)$

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