the graph of linearbequation y= 9/5x + 32 cuts the y axis at the point
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We know, on y axis, x coordinate is 0.
so put x = 0 in y = 9/5x + 32, we get
y = 9/5×0 + 32
y = 32.
So graph of the line y = 9/5x + 32 cuts the y axis at (0, 32).
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hey this is correct answer.....
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