Question

The graph of ln(R/R0) versus ln A(R = radius of a nucleus and A = its mass number) is
(a) a straight line
(b) a parabola
(c) an ellipse
(d) none of them.

Answer 1

Answer:

b is the correct answer

Answer 2

(a)The graph is a straight line

Explanation:

An element’s mass number (A) and the average nuclear radius of the nucleus (R) has the below relation:

$\mathrm{R}=\mathrm{A} 131 \mathrm{nR} \mathrm{Ro}=\mathrm{RoA} 13 \mathrm{RRo}=131 \mathrm{n} \mathrm{A}$

So, the ln(R/R0) graph versus ln A is a straight line moving via the origin with slope 1/3.

Option (b) is not the correct because the parabola’s equation is $y=4 a x 2$

Option (c) is also not correction because ellipse’s equation is  $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$