Question

The graph of the function y=2x2+bx+8 is shown. What is the value of b

Answer 1

Answer:

-12

Step-by-step explanation:

The answer is  -12 I did this on savvas and it was correct

Answer 2

Answer:

The value of b in the given function is 4.

Step-by-step explanation:

To find the value of b in the function $y=2x^2+bx+8$, we need to use the fact that the graph of a quadratic function (in this case, a parabola) is symmetric about its axis of symmetry. The axis of symmetry is a vertical line that passes through the vertex of the parabola, and its equation is given by$x = -b/2a$, where a and b are the coefficients of the $x^2$ and x terms, respectively.

Since we know that the coefficient of the $x^2$term is 2, we can plug in the values of a and b into the equation for the axis of symmetry to get:

$x = -b/2a\\x = -b/2(2)\\x = -b/4$

We also know that the vertex of the parabola lies on the axis of symmetry, and we can see from the graph that the vertex is at the point $(-1, 6)$.

Therefore, we can set $x = -1$ and $y = 6$ in the equation of the function to get:

$6 = 2(-1)^2 + b(-1) + 8\\6 = 2 - b + 8\\b = 4$

Hence, the value of b in the given function is 4.

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