The graph of the function y = f(x) is symmetrical about the line x = 2, then
(a) f (x) = - f (-x)
(b) f (2 + x) = f (2 - x)
(c) f (x) = f (-x)
(d) f (x + 2) = f (x - 2)
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Answer:
b.
when its a mirror ABOUT x =2 , then vakue of f , x ahead of 2 is same as value of f , x behind 2 .
putting x=2 in b , we get f(0) = f(4) so qualifies.
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