The graph of the linear equation 2x + 3 y = 6 cuts the y –axis at the point : 1
a. (2, 0) b. (0, 3) c. (3, 0) d. (0, 2)
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Answer:
2x+3y=6
cuts y axis at point (0,2)
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d. (0, 2)
Firstly, as we know that the point on the y-axis will have the x-coordinate as 0, this means that the point at which the graph of linear equation 2x + 3y = 6 cuts the y-axis is '(0, y)'. Hence, the point at which the graph of linear equation 2x + 3y = 6 cuts the y-axis is y(0, 2)
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