Question

The graph of the linear equation 2x+3y = 6 cuts the y-axis at the point

Answer 1

Step-by-step explanation:

The point at which the graph of linear equation 2x + 3y = 6 cuts the y-axis is (0, 2).

We have to find the point at which the graph of linear equation 2x + 3y=6 cuts the y-axis.

Firstly, as we know that the point on the y-axis will have the x-coordinate as 0, this means that the point at which the graph of linear equation 2x + 3y = 6 cuts the y-axis is '(0, y)'.

Now, substituting this coordinate into the given linear equation, we get;

2x+3y=62x+3y=6

(2\times 0)+3(y)=6(2×0)+3(y)=6

0+3y=60+3y=6

3y=63y=6

y =\frac{6}{3}y=

3

6

y = 2

Hence, the point at which the graph of linear equation 2x + 3y = 6 cuts the y-axis is y(0, 2).

please mark me as brainlisit