Question

The graph of the linear equation 2x+3y=8 cuts the y -axis is

Answer 1

Answer:

Step-by-step explanation:

In given equation, P(x)= 2x+3y-8=0; a=2, b=3, c=-8

A) Intersecting lines: -  a1/a1 is not equal to b1/b2

So, the other equation will be,  3x+3y-8=0

B) Parallel lines: - a1/a2 = b1/b2 is not equal to c1/c2

So, the other equation will be, 2x+3y-4=0

C) Coincident lines: - a1/a2 =b1/b2=c1/c2

So, the other equation will be, 4x+6y-16=0 or 2x+3y-8=0