Math, asked by mohishkhan9996, 8 months ago

The graph of the linear equation 3x + 5y = 15 cuts the x axis at the point. Write the coordinate of cutting point.​

Answers

Answered by Malhar258060
39

Answer:

hey frnd here is your answer

Step-by-step explanation:

The graph will cut x-axis at point x=5

so here point of cutting will be (5,0)

The graph will cut y-axis at point Y=3

here point of cutting will be (0,3)

The Coordinates of cutting are (x,y) =(5,3)

i hope u get your answer

plzz mark as brainlist .....

Answered by pulakmath007
6

The coordinate of cutting point is (5,0)

Given :

The graph of the linear equation 3x + 5y = 15 cuts the x axis at the point

To find :

The coordinate of cutting point

Solution :

Step 1 of 2 :

Write down the given equation

Here the given linear equation is

3x + 5y = 15

Step 2 of 2 :

Find the coordinate of cutting point

We rewrite the given equation in intercept form as below

\displaystyle \sf{ 3x + 5y = 15 }

\displaystyle \sf{ \implies  \frac{3x}{15} +  \frac{5y}{15}  = 1 }

\displaystyle \sf{ \implies  \frac{x}{5} +  \frac{y}{3}  = 1 }

So the linear equation cuts x axis at (5,0) & y axis at (0,3)

It is given that the graph of the linear equation 3x + 5y = 15 cuts the x axis at the point

Hence coordinate of cutting point is (5,0)

Note : The graph of the linear equation 3x + 5y = 15 is referred to the attachment. In the graph the point A represents (5,0) and B represents (0,3)

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. Find the point where the graph of 0.25x + 0.05y =1.00 intersects the y-axis:

https://brainly.in/question/26332017

2. Find the equation of straight line passing through the point (-4,5) and making equal intercepts on the coordinate axis.

https://brainly.in/question/25257443

#SPJ3

Attachments:
Similar questions