The graph of the linear equation 3x-5y=15,cuts the y-axis at the point?
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The point at which it cuts the y-axis the x-coordinate will be 0
Putting x = 0 in the equation,
-5y = 15
y = -3
Therefore the point of intersection in the y-axis is (0,-3)
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Step-by-step explanation:
the graph of the linear equation 3x-5y=15,cuts the y-axis at the point (0,-3)
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