The graph of the linear equation 3x + 5y = 15 cuts the y-axis at the point ?
a.)( 5 , 0 )
b.)( 3 , 0 )
c.)( 0 , 5 )
d.)( 0 , 3 )
PLEASE ANSWER FAST
Answers
Answer:
d) 0,3 and a) 5,0
is your answer
Step-by-step explanation:
3x+5y = 15
x=15-5y/3
if you= 0
then x= 15-0/3
= 15/3
= 3
if x=0
then y = 15/5
= 3
graph method
0,3
5,0
SOLUTION
TO CHOOSE THE CORRECT OPTION
The graph of the linear equation 3x + 5y = 15 cuts the y-axis at the point
a.) ( 5 , 0 )
b.) ( 3 , 0 )
c.) ( 0 , 5 )
d.) ( 0 , 3 )
EVALUATION
Here the given equation of the line is
3x + 5y = 15 - - - - - - - (1)
Now the the graph of the linear equation cuts the y-axis
So x = 0
Putting x = 0 in Equation 1 we get
0 + 5y = 15
⇒ 5y = 15
⇒ y = 3
So the required point (0,3)
FINAL ANSWER
Hence the correct option is d.)( 0 , 3 )
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