Math, asked by ayushisingh013, 8 months ago

The graph of the linear equation 3x + 5y = 15 cuts the y-axis at the point ?

a.)( 5 , 0 )
b.)( 3 , 0 )
c.)( 0 , 5 )
d.)( 0 , 3 )



PLEASE ANSWER FAST ​

Answers

Answered by nancyyadavtafs
8

Answer:

d) 0,3 and a) 5,0

is your answer

Step-by-step explanation:

3x+5y = 15

x=15-5y/3

if you= 0

then x= 15-0/3

= 15/3

= 3

if x=0

then y = 15/5

= 3

graph method

0,3

5,0

Answered by pulakmath007
4

SOLUTION

TO CHOOSE THE CORRECT OPTION

The graph of the linear equation 3x + 5y = 15 cuts the y-axis at the point

a.) ( 5 , 0 )

b.) ( 3 , 0 )

c.) ( 0 , 5 )

d.) ( 0 , 3 )

EVALUATION

Here the given equation of the line is

3x + 5y = 15 - - - - - - - (1)

Now the the graph of the linear equation cuts the y-axis

So x = 0

Putting x = 0 in Equation 1 we get

0 + 5y = 15

⇒ 5y = 15

⇒ y = 3

So the required point (0,3)

FINAL ANSWER

Hence the correct option is d.)( 0 , 3 )

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. locate the following points on the cartesian plane(aEr) (0,a),(a,0),(-a, 0),(0,-a)...

https://brainly.in/question/26822338

2. Distance of a point A(-2,0) from x-axis is _______ units.

https://brainly.in/question/28760447

Similar questions