Math, asked by ashwinbishnoi3, 19 days ago

The graph of the linear equation 3x + 5y = 6 cuts the x-axis at the point *

please ans in brief ​

Answers

Answered by uttambera538
0

The graph of the linear equation 3x + 5y = 6 cuts the x-axis at 5y.

Answered by pulakmath007
1

The graph of the linear equation 3x + 5y = 6 cuts the x-axis at the point (2,0)

Given : The equation of the line 3x + 5y = 6

To find : The point where graph of the linear equation 3x + 5y = 6 cuts the x-axis

Solution :

Step 1 of 2 :

Write down the given equation of the line

The given equation of the line is

3x + 5y = 6

Step 2 of 2 :

Find the point where graph of the linear equation 3x + 5y = 6 cuts the x-axis

Since the graph of the linear equation cuts the x-axis

So ordinate of the required point = 0

Thus we have y = 0

Putting y = 0 in 3x + 5y = 6 we get

3x + ( 5 × 0 ) = 6

⇒ 3x = 6

⇒ x = 2

Hence the required point is (2,0)

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