The graph of the linear equation 3x + 5y = 6 cuts the x-axis at the point *
please ans in brief
Answers
The graph of the linear equation 3x + 5y = 6 cuts the x-axis at 5y.
The graph of the linear equation 3x + 5y = 6 cuts the x-axis at the point (2,0)
Given : The equation of the line 3x + 5y = 6
To find : The point where graph of the linear equation 3x + 5y = 6 cuts the x-axis
Solution :
Step 1 of 2 :
Write down the given equation of the line
The given equation of the line is
3x + 5y = 6
Step 2 of 2 :
Find the point where graph of the linear equation 3x + 5y = 6 cuts the x-axis
Since the graph of the linear equation cuts the x-axis
So ordinate of the required point = 0
Thus we have y = 0
Putting y = 0 in 3x + 5y = 6 we get
3x + ( 5 × 0 ) = 6
⇒ 3x = 6
⇒ x = 2
Hence the required point is (2,0)
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