the graph of the linear equation 4x+2y=12,cut the y axis at which point
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Answer:
y=0 y = 0
y=0 y = 02x - y = 4
y=0 y = 02x - y = 4x = 4/2
y=0 y = 02x - y = 4x = 4/2x = 2
y=0 y = 02x - y = 4x = 4/2x = 2hence at point (2,0) equation 2x-y=4 cuts x axis
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Answer:
the graph linear equation 4x+4y=12. it cut y axis so x= 0
4×0+2y=12
0+2y=12
so 2y= 12
ghen y = 12/ 2
therefore y = 6
the point is (0,6)
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