Question

The graph of the linear equation 4x+y=12 is a line which meets the y axis at the point

Answer 1

Step-by-step explanation:

(0, 12)

putting x is equal to zero in the above equation

4*0 + y = 12

y = 12

Answer 2

The graph of the linear equation 4x + y = 12 is a line $\displaystyle \sf{ m e e t s }$ the y axis at the point (0,12)

Given :

The equation of the line 4x + y = 12

To find :

The point where graph of the linear equation 4x + y = 12 $\displaystyle \sf{ m e e t s }$ the y axis

Solution :

Step 1 of 2 :

Write down the given equation of the line

The given equation of the line is 4x + y = 12

Step 2 of 2 :

Find the point where graph of the linear equation $\displaystyle \sf{ m e e t s }$ the y axis

The line 4x + y = 12 $\displaystyle \sf{ m e e t s }$ y axis

∴ x = 0

Putting x = 0 in 4x + y = 12 we get

( 4 × 0 ) + y = 12

⇒ 0 + y = 12

⇒ y = 12

Hence the graph of the linear equation 4x + y = 12 is a line $\displaystyle \sf{ m e e t s }$ the y axis at the point (0,12)

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